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This is an MCQ based on the Areas of Parallelograms and Triangles.
Which includes the concepts of the median, trapezium, properties of triangles, rhombus, and different types of triangles.
AE is a median to side BC of triangle ABC. If area(ΔABC) = 24 cm, then area(ΔABE) =
In the figure, ∠PQR = 90°, PS = RS, QP = 12 cm and QS = 6.5 cm. The area of ΔPQR is
In ΔPQR, if D and E are points on PQ and PR respectively such that DE || QR, then ar (PQE) is equal to
If Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Then,
Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is
If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of parallelogram is
PQRS is a parallelogram and A and B are any points on PQ and QR. If ar(PQRS) = 48 cm², then ar(ΔPBS) + ar(ΔASR) is equal to
If E, F, G and H are the mid-points of the sides of a parallelogram ABCD, respectively, then ar (EFGH) is equal to:
If P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD, then:
If ABCD and EFGH are two parallelograms between same parallel lines and on the same base, then:
A median of a triangle divides it into two
If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of the parallelogram will be:
BCD is quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD is
Is a rectangles
Is a parallelogram
Is a rhombus
Need not be any of (a), (b) or (c).
The median of a triangle divides it into two
Isosceles triangle
Congruent triangles
Right angled triangle
Triangles of equal areas
ABCD is a quadrilateral whose diagonal AC divides it in two parts of equal area, then ABCD is a
Rectangle
Rhombus
Parallelogram
Need not be any of (a), (b) or (c)
