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Learning outcomes:
1. add, subtract, multiply, and divide functions.
2. Find compositions of one function with another function.
3. Use combinations of functions to model and solve real-life problems.
1.
1 Functions and Their Graphs
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2.
1.5 Combinations of Functions
Copyright © Cengage Learning. All rights reserved.
3.
What You Should Learn
• Add, subtract, multiply, and divide functions.
• Find compositions of one function with another
function.
• Use combinations of functions to model and
solve real-life problems.
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4.
Arithmetic Combinations of Functions
Just as two real numbers can be combined by the
operations of addition, subtraction, multiplication, and
division to form other real numbers, two functions can be
combined to create new functions. When
f (x) = 2x – 3 and g (x) = x2 – 1
you can form the sum, difference, product, and quotient of
f and g as follows.
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5.
Arithmetic Combinations of Functions
f (x) + g (x) = (2x – 3) + (x2 – 1)
Sum
= x2 + 2x – 4
f (x) – g (x) = (2x – 3) – (x2 – 1)
Difference
= –x2 + 2x – 2
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6.
Arithmetic Combinations of Functions
f (x) g (x) = (2x – 3)(x2 – 1)
Product
= 2x3 – 3x2 – 2x + 3
Quotient
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7.
Arithmetic Combinations of Functions
The domain of an arithmetic combination of functions f
and g consists of all real numbers that are common to the
domains of f and g. In the case of the quotient
there is the further restriction that g (x) 0.
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8.
Example 1 – Finding the Sum of Two Functions
Given f (x) = 2x + 1 and g (x) = x2 + 2x – 1, find (f + g) (x).
Then evaluate the sum when x = 2.
(f + g) (x) = f (x) + g (x)
= (2x + 1) + (x2 + 2x – 1)
= x2 + 4x
When x = 2, the value of this sum is
(f + g) (2) = 22 + 4(2)
= 12. 8
9.
Compositions of Functions
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10.
Compositions of Functions
Another way of combining two functions is to form the
composition of one with the other.
For instance, when f (x) = x2 and g (x) = x + 1, the
composition of f with g is
f (g (x)) = f (x + 1)
= (x + 1)2.
This composition is denoted as f g and is read as
“f composed with g”.
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11.
Compositions of Functions
Figure 1.50
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12.
Example 5 – Forming the Composition of f with g
Find (f g)(x) for and g (x) = x – 1, x 1.
If possible, find (f g)(2) and (f g)(0).
The composition of f with g is
(f g) (x) = f (g (x)) Definition of f g
= f (x – 1) Definition of g (x)
= Definition of f (x)
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13.
Example 5 – Solution cont’d
The domain of f g is [1, ) (See Figure 1.51).
Figure 1.51
(f g) (2) = =1
is defined, but (f g)(0) is not defined because 0 is not in the
domain of f g. 13
15.
Example 10 – Bacteria Count
The number N of bacteria in a refrigerated petri dish is
given by
N(T) = 20T2 – 80T + 500, 2 T 14
where T is the temperature of the petri dish (in degrees
Celsius). When the petri dish is removed from refrigeration,
the temperature of the petri dish is given by
T (t) = 4t + 2, 0 t 3
where t is the time (in hours).
a. Find the composition N (T(t)) and interpret its meaning in
context.
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16.
Example 10 – Bacteria Count cont’d
b. Find the number of bacteria in the petri dish when t = 2
hours.
c. Find the time when the bacteria count reaches 2000.
a. N (T(t)) = 20(4t + 2)2 – 80(4t + 2) + 500
= 20(16t2 + 16t + 4) – 320t – 160 + 500
= 320t2 + 320t + 80 – 320t – 160 + 500
= 320t2 + 500
The composite function N (T(t)) represents the number of
bacteria as a function of the amount of time the petri dish
has been out of refrigeration.
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17.
Example 10 – Solution cont’d
b. When t = 2 the number of bacteria is
N = 320(2)2 + 420
= 1280 + 420
= 1700.
c. The bacteria count will reach N = 2000 when
320t2 + 420 = 2000.
You can solve this equation for t algebraically as follows.
320t2 + 420 = 2000
320t2 = 1580 17
18.
Example 10 – Solution cont’d
So, the count will reach 2000 when t 2.22 hours. Note
that the negative value is rejected because it is not in the
domain of the composite function.
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19.
Example 10 – Solution cont’d
To confirm your solution, graph the equation
N = 320t2 + 420 as shown in Figure 1.54. Then use the
zoom and trace features to approximate N = 2000 when
t 2.22 as shown in Figure 1.55.
Figure 1.54 Figure 1.55
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