Finding The Solution To An Inequality With Division

This is an MCQ-based quiz for GRE on How To Find The Solution To An Inequality With Division.

If you multiply or divide both sides of an inequality by the same positive number, the inequality remains true. But if you multiply or divide both sides of an inequality by a negative number, the inequality is no longer true.

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Each of the following is equivalent to xy/z * (5(x + y)) EXCEPT:

xy(5y + 5x)/z xy(5x + 5y)/z 5x²y + 5xy²/z 5x² + y²/z

Let S be the set of numbers that contains all of values of x such that 2x + 4 < 8. Let T contain all of the values of x such that -2x +3 < 8. What is the sum of all of the integer values that belong to the intersection of S and T?

0 -2 -7 -3 2

|3x+4|≤29 |2y+6|≤18 Quantity A: The smallest possible value for x Quantity B: The smallest possible value for y Which of the following is true? The smallest possible value for Which of the following is true?

The two quantities are equal. Quantity A is larger. Quantity B is larger. A comparison cannot be detemined from the given information.

For how many positive integers, x, is it true that x^4<27x?

More than

None

Solve for x.

4x+3y=6

2x+2y=4

x=2

x=0

x>0

x=3/4

x=-2

Solve for the y-intercept:

3y+11≥5y+6x−1

-3