This is an MCQ-based quiz for GRE on **How To Find The Solution To A Quadratic Equation**.

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).

If f(x) = -x^2 + 6x - 5, then which could be the value of a if f(a) = f(1.5)?

Solve for x: 2(x + 1)^2 – 5 = 27

Solve 3x^2 + 10x = –3

Solve for x: x^2 + 4x = 5

-1 or 5

-1

-5 or 1

None of the other answers

-5

Solve for x: (x^2 – x) / (x – 1) = 1

x = 1

No solution

x = 2

x = -2

x = -1

x^2 – 3x – 18 = 0

Quantity A: x

Quantity B: 6

Quantity B is greater.

The relationship cannot be determined from the information given.

The two quantities are equal.

Quantity A is greater

7 ft

20 ft

24 ft

10 ft

5 ft

What is the sum of all the values of that satisfy:

3x^2−5x=2x+6

2

3

2/3

14/15

7/3

4x^2+5x=3x^2−x−5

Quantity A: x

Quantity B: 1

A comparison cannot be detemined from the given information.

The two quantities are equal.

Quantity A is larger.

Quantity B is larger.

Quiz/Test Summary

Title:
Finding the Solution to a Quadratic Equation

Questions:
10

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