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This is an MCQ-based quiz for GRE on How To Find Excluded Values.
This includes Excluded values which are values that will make the denominator of a fraction equal to 0. You can't divide by 0, so it's very important to find these excluded values when you're solving a rational expression.
Which of the following are answers to the equation below? (x^2 - 4) / (x^2+5x+6) =0 I. -3 II. -2 III. 2
If f(x)=(x^2−25) / (3x^2+4x−7) then which values of x cannot exist?
x=1
x= -1
x=5
x= -5
x= -7
Which of the following provides the complete solution set for |2 - z| > 0 ?
z<2
No solutions
z=2
z!=2
z>2
If f(x) = (x^2 - 16)^1/2 then which cannot be an x value?
x=3.5
x= -6.7
x=16
x=4
x= -5.2
Find the excluded values of the following algebraic fraction
(2x^2−5x−12) / (x^2−11x+28)
x!= -11
x!=4
x!=4,7
The numerator cancels all the binomials in the denomniator so ther are no excluded values.
x!=7
