Percentage problems with their solutions

Contributed by:
Diego
Through this pdf, you will learn some of the percentage problems with their solutions.
1. Percent Word Problems
Ratio and proportion method
Here are several aids that will help you solve word problems:
1. Make sure you understand the question that is asked
2. Sort out the information to make a basic percent problem, such
as “30% of what is 17?”
3. Sometimes, you will have to subtract or add some of the numbers.
4. The base will always be the original number, price, or total.
Some examples of percent word problems.
A baseball pitcher won 80% of the games he pitched. If he pitched 35
ballgames, how many games did he win?
80% of 35 is what?
1. Multiply the opposites
80 x 35 = 2800
80 2. Divide by the remaining number
100 35 28
100 2800
28 games
Jerry, an electrician, worked 7 months out of the year. What percent
of the year did he work? (round answer to the nearest hundredth)
What percent of 12 is 7? 12 months = 1 year
1. Multiply the opposites
7 7 x 100 = 700
100 12 2. Divide by the remaining number
58.33
12 700.00
58.33% (rounded to hundredth)
Percent Word Problems Handout
Revised @2009 MLC page 1 of 8
2. Sometimes the information needed to solve a percent word problem is not
stated directly. You will need to sort out the numbers given in the problem.
Organizing all the information into a box format will help you see what
numbers you have and what you need.
Some examples.
There are 28 students in a class. Sixteen of those students are men.
What percent of the class are women? (Round to the nearest tenth)
Men % 16 28 total students
Women % 12 -16 men
Total 100% 28 12 women
12 is what % of 28? 1. Multiple the opposites
100 x 12 = 1200
12 2. Divide by the remaining number
100 28 42.85
28 1200.00
42.9%
`
Donovan took a math test and got 35 correct and 10 incorrect answers.
What was the percentage of correct answers? (Round to the nearest
hundredth)
Correct answers % 35 35 correct answers
Incorrect answers % 10 +10 incorrect answers
Total answers 100% 45 45 total answers
35 is what % of 45?
1. Multiple the opposites
35 100 x 35 = 3500
2. Divide by the remaining number
100 45
77.777
45 3500.000
77.78% (rounded to hundredth)
Percent Word Problems Handout
Revised @2009 MLC page 2 of 8
3. Percent Word Problems
Directions: Set up a basic percent problem. Sometimes you will have to do
extra steps to solve the problem. Follow rounding directions. Answers and
solutions start on page 6.
1) A student earned a grade of 80% on a math test that had
20 problems. How many problems on this test did the
student answer correctly? (round to the nearest whole
number)
2) There are 36 carpenters in a crew. On a certain day, 29
were present. What percent showed up for work? (round to
the nearest tenth)
3) A metal bar weighs 8.15 ounces. 93% of the bar is silver.
How many ounces of silver are in the bar? (round to the
nearest thousandth)
4) A woman put $580 into a savings account for one year. The
rate of interest on the account was 6½%. How much was the
interest for the year in dollars and cents? (Round to the
nearest cent)
Percent Word Problems Handout
Revised @2009 MLC page 3 of 8
4. 5) A student answered 86 problems on a test correctly and
received a grade 98%. How many problems were on the test,
if all the problems were worth the same number of points?
(Round to the nearest whole number)
6) Manuel found a wrecked Trans-Am that he could fix. He
bought the car for 65% of the original price of $7200.
What did he pay for the car? (Round to nearest dollar)
7) Pamela bought an electric drill at 85% of the regular price.
She paid $32.89 for the drill. What was the regular price?
(Round to the nearest cent)
2
8) A crew is made up of 8 men; the rest are women. 66 % of
3
the crew are men. How many people are in the crew?
9) Ben earns $12,800 a year. About 15% is taken out for taxes.
How much is taken out for taxes?
Percent Word Problems Handout
Revised @2009 MLC page 4 of 8
5. 10) At a sale, shirts were sold for $15 each. This price was 80%
of their original price. What was the original price?
11) There are 32 students in a class. Nine of those students are
women. What percent are men? (round to the nearest tenth)
12) The Royals softball team played 75 games and won 55 of
them. What percent of the games did they lose? (round to
the nearest tenth)
Percent Word Problems Handout
Revised @2009 MLC page 5 of 8
6. Answer Key
80 Multiply the opposites:
100 20 80 x 20 = 1600
Divide by the remaining number:
16
100 1600
16 problems
29 Multiply the opposites:
100 36 29 x 100 = 2900
Divide by the remaining number:
80 .55
36 2900 .00
80.6%
93 Multiply the opposites:
100 8.15 93 x 8.15 = 757.95
Divide by the remaining number:
7.5795
100 757 .9500
7.580 ounces
61 Multiply the opposites:
4. 2
100 580 6 ½ x 580 = 3770
Divide by the remaining number:
37 .70
100 3770 .00
$37.70
98 86 Multiply the opposites:
100 100 x 86 = 8600
Divide by the remaining number:
87 .7
98 8600 .0
88 problems (rounded to nearest whole)
Percent Word Problems Handout
Revised @2009 MLC page 6 of 8
7. 65 Multiply the opposites:
100 7200 65 x 7200 = 468,000
Divide by the remaining number:
4680
100 468000
$4680
85 32.89 Multiply the opposites:
100 100 x 32.89 = 3289
Divide by the remaining number:
38 .694
85 3289 .000
$38.69
66 2 8 Multiply the opposites:
8. 3
100 x 8 = 800
100
Divide by the remaining number:
4
800 200 800 3 12
800 66 2
3 1 3 1 200 1
12 1
15 Multiply the opposites:
100 12,800 15 x 12,800 = 192,000
Divide by the remaining number:
1920
100 192000
$1920
80 15 Multiply the opposites:
100 100 x 15 = 1500
Divide by the remaining number:
18 .75
80 1500 .00
Percent Word Problems Handout
Revised @2009 MLC page 7 of 8
8. $18.75
Total 100% 32 32
Men 23 9
Women 9 23
23 Multiply the opposites:
100 32 100 x 23 = 2300
Divide by the remaining number:
71.87
32 2300.00
71.9%(rounded to nearest tenth)
Total 100% 75 75
Won 55 55
Lost 20 20
20 Multiply the opposites:
100 75 100 x 20 = 2000
Divide by the remaining number:
26.667
75 2000.000
26.7% games lost (rounded to tenth)
Percent Word Problems Handout
Revised @2009 MLC page 8 of 8