If – 3x + 17 < – 13, then

Given that x, y and b are real numbers and x < y, b < 0, then

If |x −1| > 5, then

If |x – 7|/(x – 7) ≥ 0, then

If | x − 1| > 5, then

The solution of |2/(x – 4)| > 1 where x ≠ 4 is

The solution of the inequality |x – 1| < 2 is

The graph of the inequalities x ≥ 0, y ≥ 0, 2x + y + 6 ≤ 0 is

Solve: 2x + 1 > 3

Breadth > 20 cm

Length < 20 cm

Breadth x ≥ 20 cm

Length ≤ 20 cm

If (|x| – 1)/(|x| – 2) ≥ 0, x ∈ R, x ± 2 then, the interval of x is

(-∞, -2) ∪ [-1, 1]

[-1, 1] ∪ (2, ∞)

(-∞, -2) ∪ (2, ∞)

(-∞, -2) ∪ [-1, 1] ∪ (2, ∞)

If x² < -4 then, the value of x is

(-2, 2)

(2, ∞)

(-2, ∞)

No solution

If -2 < 2x – 1 < 2 then, the value of x lies in the interval

(1/2, 3/2)

(-1/2, 3/2)

(3/2, 1/2)

(3/2, -1/2)

The graph of the inequations x ≤ 0 , y ≤ 0, and 2x + y + 6 ≥ 0 is

Exterior of a triangle

A triangular region in the 3rd quadrant

In the 1st quadrant

None of these

If |x| < -5 then, the value of x lies in the interval

(-∞, -5)

(∞, 5)

(-5, ∞)

No Solution